(2x^3-34x-80)/(x-5)

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Solution for (2x^3-34x-80)/(x-5) equation:


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

(2*x^3-(34*x)-80)/(x-5) = 0

(2*x^3-34*x-80)/(x-5) = 0

2*x^3-34*x-80 = 0

2*(x^3-17*x-40) = 0

x^3-17*x-40 = 0

{ 1, -1, 2, -2, 4, -4, 5, -5, 8, -8, 10, -10, 20, -20, 40, -40 }

1

x = 1

x^3-17*x-40 = -56

1

-1

x = -1

x^3-17*x-40 = -24

-1

2

x = 2

x^3-17*x-40 = -66

2

-2

x = -2

x^3-17*x-40 = -14

-2

4

x = 4

x^3-17*x-40 = -44

4

-4

x = -4

x^3-17*x-40 = -36

-4

5

x = 5

x^3-17*x-40 = 0

5

x-5

x^2+5*x+8

x^3-17*x-40

x-5

5*x^2-x^3

5*x^2-17*x-40

25*x-5*x^2

8*x-40

40-8*x

0

x^2+5*x+8 = 0

DELTA = 5^2-(1*4*8)

DELTA = -7

DELTA < 0

x in { 5}

2*(x-5) = 0

2 = 0

x belongs to the empty set

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